A thin circular ring of mass M and radius R rotates about an axis through its centre

A thin circular ring of mass M and radius R rotates about an axis through its centre and perpendicular to its plane, with a constant angular velocity ?. Four small spheres each of mass m (negligible radius) are kept gently to the opposite ends of two mutually perpendicular diameters of the ring. The new angular velocity of the ring will be

Options

(a) M?/4m
(b) [M+4m/M] ?
(c) [M/M-4m] ?
(d) [M/M+4m] ?

Correct Answer:

[M/M+4m] ?

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. The moment of inertia of a thin uniform rod of mass M and length L about an axis
  2. The vector sum of two forces is perpendicular to their vector difference. In that case,
  3. The motion of a particle along a straight line is described by equation
  4. A slab consists of two parallel layers of two different materials of same thickness
  5. The force F acting on a particle of mass m is indicated by the force-time graph