A rod of weight W is supported by two parallel knife edges A and B is in equilibrium

A rod of weight W is supported by two parallel knife edges A and B is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is

Options

(a) Wd/x
(b) W(d-x)/x
(c) W(d-x)/d
(d) Wx/d

Correct Answer:

W(d-x)/d

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. The potential energy of particle in a force field is U = A/r² – b/r, where A and B
  2. A man of 50 kg mass is standing in a gravity free space at a height
  3. The radius of orbit of a planet is two times that of the earth. The time period
  4. Two masses of 9 g and 6 g are connected with a string which is passing over a frictionless
  5. The apparent weight of the body of mass 10 kg when it is travelling upwards with