A rod of weight W is supported by two parallel knife edges A and B is in equilibrium

A rod of weight W is supported by two parallel knife edges A and B is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is

Options

(a) Wd/x
(b) W(d-x)/x
(c) W(d-x)/d
(d) Wx/d

Correct Answer:

W(d-x)/d

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. A certain mass of Hydrogen is changed to Helium by the process of fusion
  2. In the experiment for determination of velocity of sound in air,
  3. A body starts from rest, what is the ratio of the distance travelled by the body
  4. A parallel plate air capacitor is charged to a potential difference of V volts.
  5. If F⃗ is the force acting on a particle having position vector r⃗ and ? ⃗ be the torque