A radioactive substance decays to 1/16th of its initial activity in 40 days.

A radioactive substance decays to 1/16th of its initial activity in 40 days. The half-life of the radioactive substance expressed in days is

Options

(a) 2.5
(b) 5
(c) 10
(d) 20

Correct Answer:

10

Explanation:

N/N₀ = (1/2)ⁿ

(1/16) = (1/2)ⁿ

n = 4

Half life = t / n = 40 / 4 = 10 day

admin:

Related Questions

  1. The energy of groundstate (n=1) of hydrogen level is -13.6 eV. The ionistation
  2. In which case positive work has to be done in seperating them?
  3. The maximum kinetic energy of the photoelectrons depends only on
  4. A 0.5 kg ball moving with a speed of 12 m/s strikes a hard wall at an angle
  5. When the wavelength of sound changes from 1 m to 1.01 m,