A photon of energy 10.2 eV collide inelastically with hydrogen atom in ground state

A photon of energy 10.2 eV collide inelastically with hydrogen atom in ground state after few microseconds another photon of energy 15 eV collides inelastically with same hydrogen atom. Finally by a suitable detector we find

Options

(a) photon of energy 3.4 eV and electron of energy 1.4 eV
(b) photon of energy 10.2 eV and electron of energy 1.4 eV
(c) two photons of energy 3.4 eV
(d) two photons of energy 10.2 eV

Correct Answer:

photon of energy 10.2 eV and electron of energy 1.4 eV

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. The ratio of radii of planets A and B is K₁ and ratio of accelerations
  2. If radius of the ₁₃Al²⁷ nucleus is taken to be Rᴀı, then the radius of ₅₃Te¹²⁵ nucleus
  3. A conveyor belt is moving at a constant speed of 2 m/s. A box is gently dropped on it
  4. If potential(in volts) in a region is expressed as V(x,y,z) = 6xy – y + 2yz,
  5. Which of the following parameters does not characterize the thermodynamic state