A particle is executing a simple harmonic motion. Its maximum acceleration

A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β. Then, its time period of vibration will be

Options

(a) β²/α
(b) 2πβ/α
(c) β²/α²
(d) α/β

Correct Answer:

2πβ/α

Explanation:

As, we know, in Simple Harmonic Motion
Maximum acceleration of the particle, α = Aω²
Maximum velocity, β = Aω
⇒ ω = α / β
⇒ T = 2π / ω = 2πβ / α [Since, ω = 2π / T].

admin:

Related Questions

  1. Two thin long conductors seprated by a distance d carry currents
  2. The electromagnetic waves detected using a thermopile and used in physical therapy
  3. In refraction, light waves are bent on passing from one medium to the second medium
  4. A galvanometer has a coil of resistance 100 ohm and gives a full-scale deflection
  5. The length of an elastic string is a metre when the longitudinal tension is 4N and b