A particle free to move along X-axis has potential energy given as U(X) =k(1-e⁻ˣ²)

A particle free to move along X-axis has potential energy given as U(X) =k(1-e-ˣ²),where k is a positive constant of appropriate dimension.Then, for -a

Options

(a) at points away from the origin, the particle is in unstable equilibrium
(b) for any finite non-zero value of x,there is a force directed away from the origin
(c) if its total mechanical energy isk/2, it has its minimum kinetic energy at the origin
(d) if its total mechanical energy isk/2, it has its maximum kinetic energy at the origin

Correct Answer:

if its total mechanical energy isk/2, it has its maximum kinetic energy at the origin

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. When the wavelength of sound changes from 1 m to 1.01 m,
  2. A car sounding a horn of frequency 100 Hz passes an observer. The ratio
  3. Two small spherical shells A and B are given positive charges of 9C and 4C
  4. Eddy currents are used in
  5. A tube of length L is filled completely with an incompressible liquid of mass