A particle free to move along X-axis has potential energy given as U(X) =k(1-e⁻ˣ²)

A particle free to move along X-axis has potential energy given as U(X) =k(1-e-ˣ²),where k is a positive constant of appropriate dimension.Then, for -a

Options

(a) at points away from the origin, the particle is in unstable equilibrium
(b) for any finite non-zero value of x,there is a force directed away from the origin
(c) if its total mechanical energy isk/2, it has its minimum kinetic energy at the origin
(d) if its total mechanical energy isk/2, it has its maximum kinetic energy at the origin

Correct Answer:

if its total mechanical energy isk/2, it has its maximum kinetic energy at the origin

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. Photocells convert
  2. Initial angular velocity of a circular disc of mass M is ?¬ツチ.Then, two small spheres
  3. A piece of iron is heated in a flame. It first comes dull red then becomes reddish
  4. The impurity atoms with which pure silicon may be doped to make it a p-type
  5. Rate of photoelectric emission is proportional to