A particle executing simple harmonic motion of amplitude 5 cm has maximum

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is

Options

(a) 4 Hz
(b) 3 Hz
(c) 2 Hz
(d) 1 Hz

Correct Answer:

1 Hz

Explanation:

a = 5 cm, vₘₐₓ = 31.4 cm/s

vₘₐₓ = ωa ⇒ 31.4 = 2πʋ × 5

⇒ 31.4 = 10 × 31.4 × ʋ

⇒ ʋ = 1 Hz

admin:

Related Questions

  1. When photons of energy hν are incident on the surface of photosensitive
  2. The electric field in a certain region is given by E=5i ̂-3ĵ kV/m. The potential
  3. The instantaneous values of alternating current and voltages in a circuit are given as
  4. Three resistances 2Ω, 3Ω and 4Ω are connected in parallel. The ratio of currents passing
  5. Three particles A,B and C are thrown from the top of a tower with the same speed.