A meter stick of mass 400 g is pivoted at one end and displaced through an angle 60°.

A meter stick of mass 400 g is pivoted at one end and displaced through an angle 60°. The increase in its potential energy is

(a) 2 J
(b) 3 J
(c) 0 J
(d) 1 J

1 J

Change in potential energy = mg/(1/2) (1-cosθ)
Given: mass = 400g = 0.4 kg and angle = 60°
Therefore, ∆U = 0.4 × 10 × (1/2) × (1-cos 60°) = 1 J.

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