A common emitter amplifier is designed with n-p-n transistor (α=0.99).

A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be

Options

(a) 9900
(b) 99
(c) 9.9
(d) 990

Correct Answer:

990

Explanation:

Voltage gain = β × Resistance gain

β = α/(1-α) = 0.99 / (1-0.99) = 99

Resistance gain = (10 × 10³) = 10

Voltage gain = 99 × 10 = 990

admin:

Related Questions

  1. If in a L-R series circuit the power factor is 1/2 and R=100Ω, then the value of L is,
  2. The angle between the dipole moment and electric field at any point on the equatoria
  3. Ist law of thermadynamics is based on
  4. In a diffraction pattern due to a singleslit of width a, the first minimum is observed
  5. A potentiometer wire of length 100cm has a resistance of 10Ω. It is connected in series