A common emitter amplifier is designed with n-p-n transistor (α=0.99).

A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be

Options

(a) 9900
(b) 99
(c) 9.9
(d) 990

Correct Answer:

990

Explanation:

Voltage gain = β × Resistance gain

β = α/(1-α) = 0.99 / (1-0.99) = 99

Resistance gain = (10 × 10³) = 10

Voltage gain = 99 × 10 = 990

admin:

Related Questions

  1. The energy released by the fission of one uranium atom is 200 MeV.
  2. A body of weight W newton is at the surface of the earth.
  3. A body starts from rest, what is the ratio of the distance travelled by the body
  4. A boy whirls a stone in a horizontal circle of radius 1.5 m and at height 2.0 m
  5. Electric field intensity at a point in between two parallel sheets due to like