A common emitter amplifier is designed with n-p-n transistor (α=0.99).

A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be

Options

(a) 9900
(b) 99
(c) 9.9
(d) 990

Correct Answer:

990

Explanation:

Voltage gain = β × Resistance gain

β = α/(1-α) = 0.99 / (1-0.99) = 99

Resistance gain = (10 × 10³) = 10

Voltage gain = 99 × 10 = 990

admin:

Related Questions

  1. A galvanometer of 50 Ω resistance has 25 divisions. A current of 4×10⁻⁴ A gives
  2. Two sources of sound placed close to each other are emitting progressive waves
  3. Two balls are dropped from same height at 1 second interval of time.
  4. Two bulbs 60 W and 100 W designed for voltage 220 V are connected in series
  5. The escape velocity of a body on an imaginary planet which is thrice the radius