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When ethyl alcohol (C₂H₅OH) reacts with thionyl chloride in the presence of

When ethyl alcohol (C₂H₅OH) reacts with thionyl chloride in the presence of pyridine the product obtained is

Options

(a) CH₃CH₂Cl + HCl
(b) CH₃CH₂Cl + H₂O + SO₂
(c) CH₃CH₂Cl + Cl₂ + SO₂
(d) C₂H₅Cl + HCl + SO₂

Correct Answer:

C₂H₅Cl + HCl + SO₂

Explanation:

C₂H₅OH + SOCl₂ → C₂H₅Cl + HCl + SO₂.

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