What is the energy released by fission of 1 g of U²³⁵?

What is the energy released by fission of 1 g of U²³⁵? (Assume 200 MeV energy is liberated on fission of 1 nucleus)

Options

(a) 2.26×10⁴ kWh
(b) 1.2×10⁴ kWh
(c) 4.5×10⁴ kWh
(d) 2.5×10⁴ kWh

Correct Answer:

2.26×10⁴ kWh

Explanation:

Energy released in one fission of ₉₂U²³⁵ nucleus = 200 MeV

Mass of uranium = 1g

We know that, 235 g of U²³⁵ has 6.023 × 10²³ atoms of nuclei.

Energy released in fission of 1g of U²³⁵,

E = (6.023 × 10²³ × 1 × 200) / 235 = 5.1 × 10²³ MeV

= 5.1 × 10²³ × 1.6 × 10⁻³ J

= [(5.1 × 10²³ × 1.6 × 10⁻³) / 3.6 × 10⁶] kWh

= 2.26 × 10⁴ kWh

admin:

Related Questions

  1. A DC ammeter has resistance 0.1Ω and its current ranges 0-100A. If the range
  2. A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude
  3. A capacitor of 10 µF charged upto 250 volt is connected in parallel with another
  4. At the first minimum adjacent to the central maximum of a single-slit diffraction
  5. Order of e/m ratio of proton, α-particle and electron is