What is the energy released by fission of 1 g of U²³⁵? (Assume 200 MeV energy is liberated on fission of 1 nucleus)

Options

(a) 2.26×10⁴ kWh
(b) 1.2×10⁴ kWh
(c) 4.5×10⁴ kWh
(d) 2.5×10⁴ kWh

Correct Answer:

2.26×10⁴ kWh

Explanation:

Energy released in one fission of ₉₂U²³⁵ nucleus = 200 MeV

Mass of uranium = 1g

We know that, 235 g of U²³⁵ has 6.023 × 10²³ atoms of nuclei.

Energy released in fission of 1g of U²³⁵,

E = (6.023 × 10²³ × 1 × 200) / 235 = 5.1 × 10²³ MeV

= 5.1 × 10²³ × 1.6 × 10⁻³ J

= [(5.1 × 10²³ × 1.6 × 10⁻³) / 3.6 × 10⁶] kWh

= 2.26 × 10⁴ kWh