Two resistors of 6Ω and 9Ω are connected in series to a 120 V source.

Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power consumed by 6Ω resistor is

Options

(a) 384Ω
(b) 616Ω
(c) 1500Ω
(d) 1800Ω

Correct Answer:

384Ω

Explanation:

Equivalent resistance in series = 6 + 9 = 15 Ω

Current flow in circuit, i = V / R = 120 / 15 = 8 A

Voltage in 6Ω resistor, V = iR = 8 × 6 = 48 V

Power consumed by 6Ω resistor,

P = V² / R = (48 × 48) / 6 = 8 × 48 = 384 W

admin:

Related Questions

  1. A mass of 2.0 kg is put on a flat plan attached to a vertical spring fixed on the ground
  2. An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor
  3. A galvanometer coil has a resistance of 15 ohm and gives full scale deflection
  4. A bullet comes out of the barrel of gun of length 2m with a speed of 800 m/s
  5. A metal wire of circular cross-section has a resistance R₁. The wire is now stretched