Two resistors of 6Ω and 9Ω are connected in series to a 120 V source.

Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power consumed by 6Ω resistor is

Options

(a) 384Ω
(b) 616Ω
(c) 1500Ω
(d) 1800Ω

Correct Answer:

384Ω

Explanation:

Equivalent resistance in series = 6 + 9 = 15 Ω

Current flow in circuit, i = V / R = 120 / 15 = 8 A

Voltage in 6Ω resistor, V = iR = 8 × 6 = 48 V

Power consumed by 6Ω resistor,

P = V² / R = (48 × 48) / 6 = 8 × 48 = 384 W

admin:

Related Questions

  1. Two conducting spheres of radii 5 cm and 10 cm are given a charge of 15 μC each.
  2. A microscope is having objective of focal length 1 cm and eye-piece of focal length 6 cm.
  3. A coil of resistance 20 ohm and inductance 5H is connected with a 100V battery
  4. A flywheel rotating about a fixed axis has a kinetic energy of 360 J when
  5. The position x of a particle with respect to time t along x-axis is given