Two particles of masses m₁ m₂ move with initial velocities u₁ and u₂

Two particles of masses m₁ m₂ move with initial velocities u₁ and u₂ .On collision, one of the particle s get excited to higher level, after absorbing energy E.If final velocities of particles be v₁ and v₂, then we must have

Options

(a) m₁²u₁+ m₂²u₂ -E = m₁²v₁+ m₂²v₂
(b) 1/2 m₁u₁²+m₂ u₂² = 1/2 m₁v₁²+ 1/2 m₂v₂² -E
(c) 1/2 m₁u₁²+m₂ u₂² -E = 1/2 m₁v₁²+ 1/2 m₂v₂²
(d) 1/2 m₁u₁²+m₂ u₂² +E = 1/2 m₁v₁²+ 1/2 m₂v₂²

Correct Answer:

1/2 m₁u₁²+m₂ u₂² -E = 1/2 m₁v₁²+ 1/2 m₂v₂²

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. The number of photons of wavelength of 540 nm emitted per second by an electric bulb
  2. A short linear object of length L lies on the axis of a spherical mirror of focal
  3. A particle under the action of a constant force moves from rest upto 20 seconds
  4. A bucket full of water is revolved in a vertical circle of 2m
  5. The maximum velocity of a particle, executing simple harmonic motion with an amplitude