There are two containers containing gases,one at pressure 30 atm and volume 20 mL and the other at pressure 25 atm.What will be the volume of the container when two are mixed
Options
(a) 24 mL
(b) 20 mL
(c) 26 mL
(d) none of these
Correct Answer:
24 mL
Explanation:
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p1v1 = p2v2
now substitute the values we will get
v2 = 24 ml
now apparently the volumes are mixed it should have gone like
v = v1 + v2
and v = 24 + 20
therefore final volume when to containers are mixed = 44 ml
P1V1=P2V2
30x20=25xV2
V2= 30x20/25
By solving
V2=24ml