The work done during the expansion of a gas from a volume of 4 dm³ to 6 dm³

The work done during the expansion of a gas from a volume of 4 dm³ to 6 dm³ against a constant external pressure of 3 atm is (1atm = 101.32 J)

Options

(a) -6 J
(b) -608 J
(c) ⁺304 J
(d) -304 J

Correct Answer:

-608 J

Explanation:

Work = -P(ext) x volume change =
-3 x 101.32 x (6 – 4)
= -6 x 101.32 = -607.92 J = -608 J

admin:

Related Questions

  1. Chloroform gives a trichloro derivative of an alcohol on reaction with
  2. The vacant space in bcc lattice unit cell is
  3. Which is correct about zero order reaction
  4. Salt cake is
  5. When a neutral atom is converted into a cation, there is