The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures T₁ and T₂ (T₁ > T₂). The rate of heat transfer, dQ/dt through the rod in a steady state is given by:

Options

(a) dQ/dt = k(T₁ – T₂) / LA
(b) dQ/dt = kLA (T₁ – T₂)
(c) dQ/dt = kA (T₁ – T₂) / L
(d) dQ/dt = kL (T₁ – T₂) / A

Correct Answer:

dQ/dt = kA (T₁ – T₂) / L

Explanation:

dQ / dt = kA (T₁ -T₂) / L
[(T₁ -T₂) is the temperature difference]