Navigate

The total energy of an electron in the first excited state of hydrogen atom

The total energy of an electron in the first excited state of hydrogen atom is about -3.4 eV. Its kinetic energy in this state is

Options

(a) 3.4 eV
(b) 6.8 eV
(c) -3.4 eV
(d) -6.8 eV

Correct Answer:

3.4 eV

Explanation:

KE. = |(1/2) P.E.|
But P.E. is negavite
.·. Total energy = |(1/2) P.E.| – P.E. = – P.E. / 2 = – 3.4 eV
.·. K.E. = + 3.4 eV

AIPMT2005
admin:

Related Questions

  1. A train of mass 2x 10⁵ kg has a constant speed of 20 m/s up a hill inclined
  2. Two coils have the mutual inductance of 0.05 H.
  3. A horizontal straight conductor kept in north-south direction falls under gravity. Then
  4. A particle of mass m is projected with velocity v making an angle of 45° with
  5. The electric potential at a point in free space due to a charge Q coulomb is Q x 10¹¹ v