Navigate

The total energy of an electron in the first excited state of hydrogen atom

The total energy of an electron in the first excited state of hydrogen atom is about -3.4 eV. Its kinetic energy in this state is

Options

(a) 3.4 eV
(b) 6.8 eV
(c) -3.4 eV
(d) -6.8 eV

Correct Answer:

3.4 eV

Explanation:

KE. = |(1/2) P.E.|
But P.E. is negavite
.·. Total energy = |(1/2) P.E.| – P.E. = – P.E. / 2 = – 3.4 eV
.·. K.E. = + 3.4 eV

AIPMT2005
admin:

Related Questions

  1. A plane wave of wavelength 6250Å is incident normally on a slit of width 2×10⁻² cm.
  2. A monoatomic gas at a pressure P, having a volume V expands isothermally
  3. Two particles are oscillating along the same line with the same frequency
  4. A transverse wave is represented by y = a sin (?t – kx)
  5. Ice is wrapped in black and white cloth. In which cases more ice will melt