The time period of a simple pendulum in a lift descending with constant acceleration g is

The time period of a simple pendulum in a lift descending with constant acceleration g is

Options

(a) T=2π√l/g
(b) T=2π√l/2g
(c) zero
(d) Infinite

Correct Answer:

Infinite

Explanation:

When the lift falls freely under gravity, effective ‘g’ for pendulum in the lift = zero.
T = 2π √(l/g) = 2π√(l/o) = Infinite.

admin:

Related Questions

  1. Pick out the correct statements from the following
  2. A heavy stone hanging from a massless string of length 15 m is projected
  3. The work function for aluminium is 4.125 eV. The cutoff wavelength for photoelectric
  4. If a given volume of water in a 220V heater is boiled in 5 min, then same volume
  5. In Young’s double slit experiment, the ratio of maximum and minimum intensities