The ratio of speed of an electron in ground state in Bohr’s first orbit of hydrogen atom

The ratio of speed of an electron in ground state in Bohr’s first orbit of hydrogen atom to velocity of light in air (c ) is

Options

(a) e²/2ε₀hc
(b) 2e²ε₀/hc
(c) e³/2ε₀hc
(d) 2ε₀hc/e²

Correct Answer:

e²/2ε₀hc

Explanation:

Velocity of electron in nᵗʰ orbit = αcz / n
where α = (e²/4πε₀) [1 / c(h/π)] = e²/2ε₀hc
v / c = αz / n = (e² × 1) / 2ε₀hc × 1 = e²/2ε₀hc

admin:

Related Questions

  1. If a gymnast, sitting on a rotating stool with his arms outstretched, suddenly
  2. A glass flask weighing 390 g having internal volume 500 cc just floats
  3. The magnetic moment of a diamagnetic atom is
  4. A cockroach is moving with a velocity v in anticlockwise direction on the rim
  5. A source and an observer approach each other with same velocity 50 m/s. If the frequency