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The radius of gyration of a solid sphere of radius r about a certain axis is r. The distance of this axis from the centre of the sphere is
Options
(a) r
(b) 0.5r
(c) √(0.6)r
(d) √(0.4)r
Correct Answer:
√(0.6)r
Explanation:
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Using parallel axis theorem ,
I =Icm(about the centre of mass) + M(mass of the sphere)h2. where h is the required distance of the axis from centre of sphere
MK2 = 2/5 MR2. + Mh2
K2= 2R2/5 + h2
R2 = 2R2/5. + h2. (given that. K=R. )
3R2/5 = h2
Which gives h=√3/5R2
h=√0.6. R. (Answer)