The pressure and temperature of 4 dm³ of carbon dioxide gas are doubled

The pressure and temperature of 4 dm³ of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be

(a) 2 dm³
(b) 3 dm³
(c) 4 dm³
(d) 8 dm³

4 dm³

P₁ = P , V₁ = 4 dm³, T₁ = T. P₂ = 2P, V₂ = ?, T₂ = 2T. From gas equation, P₁V₁ / T₁ = P₂V₂ / T₂ ⇒ P * 4 / T = 2P * V / 2T. ⇒ V = 4dm³.

KA2004

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