The potential energy of a 1 kg particle free to move along the x-axis is given by
V(x)={x⁴/4-x²/2}J.
The total mechanical energy of the particle 2 J. Then, the maximum speed (in m/s) is

Options

(a) 2
(b) 3/√2
(c) √2
(d) 1/√2

Correct Answer:

3/√2

Explanation:

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