The potential difference applied to an X-ray tube is 5 kV and the current through it

The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. The number of electrons striking the target per second is

Options

(a) 5 x 10¹⁶
(b) 1 x 10¹⁷
(c) 4 x 10¹⁵
(d) 2 x 10¹⁶

Correct Answer:

2 x 10¹⁶

Explanation:

Let n = number of electrons striking per sec.

e = 1.6 × 10⁻¹⁹ = charge on each electron

Charge per second = n × 1.6 × 10⁻¹⁹

Current = n × 1.6 × 10⁻¹⁹

3.2 × 10⁻³ = n × 1.6 × 10⁻¹⁹

n = 3.2 × 10⁻³ / 1.6 × 10⁻¹⁹ = 2 × 10¹⁶

admin:

Related Questions

  1. For CE transistor amplifier, the audio signal voltage across the collector resistance
  2. The turn ratio of a transformer is 1:2. An electrolytic dc cell of emf 2 volt is connected
  3. A electric dipole is placed at an angle of 30⁰ to a non-uniform electric field.
  4. A force of 10 newton acts on a body of mass 20 kg for 10 seconds. Change in its momentum
  5. An aeroplane flies 400m due to North and then 300m due to south and then flies