The orbital angular momentum of a p-electron is given as :

The orbital angular momentum of a p-electron is given as :

Options

(a) h/(√2π)
(b) √3 x (h/2π)
(c) √(3/2) x h/π
(d) √6 x h/2π

Correct Answer:

h/(√2π)

Explanation:

Orbital Angular Momentum = h/(2π) x √(l(l+1)). For p orbital, l=1. so => h/(2π) x √2 =? h/(√2π)

admin:

Related Questions

  1. Which of the following is ferroelectric compound
  2. Germanium of very high purity is obtained by
  3. The oxidation number of phosphorus and basicity of acid in pyrophosphoric acid
  4. The boiling point of 0.2 mol kg⁻¹ solution of X in water is greater than equimolal
  5. Which of the following does not represent the correct order of the properties