The orbital angular momentum of a p-electron is given as :

The orbital angular momentum of a p-electron is given as :

Options

(a) h/(√2π)
(b) √3 x (h/2π)
(c) √(3/2) x h/π
(d) √6 x h/2π

Correct Answer:

h/(√2π)

Explanation:

Orbital Angular Momentum = h/(2π) x √(l(l+1)). For p orbital, l=1. so => h/(2π) x √2 =? h/(√2π)

admin:

Related Questions

  1. Which of the following atomic number of uranium is the most radioactive
  2. The change in oxidation state of sulphur when sulphur dioxide is passed
  3. Phenol is heated with pthalic anhydride in the presence of concentrated H₂SO₄.
  4. 1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide
  5. The IUPAC name for Co(NH₃)₆Cl₃ is