The normality of solution containing 31.5 g of hydrated oxalic acid (H₂C₂O₄.2H₂O) in 1250 mL of solution is
Options
(a) 0.8 N
(b) 0.2 N
(c) 0.4 N
(d) 0.1 N
Correct Answer:
0.4 N
Explanation:
Normality = Number of g.equivalents of solute/volume of solution (L).
Equivalent of mass of H₂C₂O₄.
2H₂O = 126/2 = 63.
Number of g. equivalents = 31.5/63 = 1/2 .
Normality = 1/ 2 ⨯1250⨯ 1000 = 0.4 N.