The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field

The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m

Options

(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷

Correct Answer:

5 x 10⁷

Explanation:

E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹

admin:

Related Questions

  1. The horizontal range of a projectile is 4√3 times the maximum height achieved
  2. A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped
  3. Work done by an external agent in separating the parallel plate capacitor is
  4. A bimetallic strip consists of metals X and Y. It is mounted rigidly at the base as shown
  5. If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum