The kinetic energy of an electron in the first excited state is

The total energy of electron in the ground state of hydrogen atom is -13.6 eV. The kinetic energy of an electron in the first excited state is

Options

(a) 6.8 eV
(b) 13.6 eV
(c) 1.7 eV
(d) 3.4 eV

Correct Answer:

3.4 eV

Explanation:

Energy in the first excited state
= – 13.6 / n² = – 13.6 / 2² = – 3.4 eV
But K.E. = – (Total energy) = +3.4 eV.

admin:

Related Questions

  1. The time by a photoelectron to come out after the photon strikes is approximately
  2. Find out the angle of projection, if range is 4 times of maximum height
  3. 180⁰ phase difference is obtained when light ray is reflected from
  4. In circular coil, when number of turns is doubled and resistance becomes 1/4th
  5. Match the following columns about collision