![](data:image/svg+xml;charset=utf-8,<svg height="300px" width="600px" xmlns="http://www.w3.org/2000/svg" version="1.1"/>)
The horizontal range of a projectile is 4√3 times the maximum height achieved by it. The angle of projection is
Options
(a) 30⁰
(b) 45⁰
(c) 60⁰
(d) 90⁰
Correct Answer:
30⁰
Explanation:
u²sin 2θ/g = 4√3 x (u²sin 2θ/g ) ⇒ tan θ = 1/√3 .·. θ = 30°
The horizontal range of a projectile is 4√3 times the maximum height achieved
