The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is :
Options
(a) θ = tan⁻¹(1/4)
(b) θ = tan⁻¹(4)
(c) θ = tan⁻¹(2)
(d) θ = 45°
Correct Answer:
θ = tan⁻¹(4)
Explanation:
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