![](data:image/svg+xml;charset=utf-8,<svg height="300px" width="600px" xmlns="http://www.w3.org/2000/svg" version="1.1"/>)
The horizontal range and maximum height of a projectile are equal.The angle of projection is
Options
(a) θ=tan⁻¹(1/4)
(b) θ=tan⁻¹(4)
(c) θ=tan⁻¹(2)
(d) θ=45ﾟ
Correct Answer:
θ=tan⁻¹(4)
Explanation:
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