The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field

The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field, is:

Options

(a) ML²T⁻²
(b) ML⁻¹T⁻²
(c) ML²T⁻¹
(d) MLT⁻¹

Correct Answer:

ML⁻¹T⁻²

Explanation:

1/2 ?¬ツタE² represents energy density i.e., energy per unit volume.
⇒ [ 1/2 ?¬ツタE² ] = ML²T⁻² / L³
= ML⁻¹T⁻²

admin:

Related Questions

  1. In an astronomical telescope in normal adjustment a straight black line of length
  2. The electrons are emitted in the photoelectric effect from a metal surface
  3. Function of a rectifier is
  4. An unpolarised beam of intensity I₀ falls on a polaroid. The intensity
  5. At place on earth, the vertical component of earth’s magnetic field is √3 times