The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field

The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field, is:

Options

(a) ML²T⁻²
(b) ML⁻¹T⁻²
(c) ML²T⁻¹
(d) MLT⁻¹

Correct Answer:

ML⁻¹T⁻²

Explanation:

1/2 ?¬ツタE² represents energy density i.e., energy per unit volume.
⇒ [ 1/2 ?¬ツタE² ] = ML²T⁻² / L³
= ML⁻¹T⁻²

admin:

Related Questions

  1. Two coils have the mutual inductance of 0.05 H.
  2. A body of mass M hits normally a rigid wall with velocity V and bounces back
  3. A solenoid of length l metre has self inductance L henry. If number of turns
  4. An ideal gas is expanding such that PT²=constant. The coefficient of volume
  5. A thermocouple is made from two metals, antimony and bismuth. If one junction