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The current through an inductor changes from 3 A to 2 A is 1 m/s. If induced e.m.f.

The current through an inductor changes from 3 A to 2 A is 1 m/s. If induced e.m.f. in inductor is 5V then L is

Options

(a) 5×10⁻² H
(b) 5×10⁻³ H
(c) 2.5×10⁻³ H
(d) None of these

Correct Answer:

5×10⁻³ H

Explanation:

– L (di / dt) = ε ⇒ L × [(3A – 2A) / (i × 10⁻³s)] = 5 V

Therefore, L = 5 × 10⁻³ H

AFMC2006
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