The correct set of four quantum numbers for the valence electron of rubidium atom(Z=37) is

Options

(a) 5,1,1,+½
(b) 6,0,0,+½
(c) 5,0,0,+½
(d) 5,1,0,+½

Correct Answer:

5,0,0,+½

Explanation:

₃₇Rb=₃₆[Kr] 5s
Its valence electron in 5s¹.
so, n= 5
/= 0 (For s oribital)
m= 0 (As m= -/ to 0 to +/)
s= +½.