The correct bond order in the following species is

The correct bond order in the following species is

Options

(a) O₂²⁺ < O₂⁻ < O₂⁺
(b) O₂⁺ < O₂⁻ < O₂²⁺
(c) O₂⁻ < O₂⁺ < O₂²⁺
(d) O₂²⁺ < O₂⁺ < O₂⁻

Correct Answer:

O₂⁻ < O₂⁺ < O₂²⁺

Explanation:

O₂⁺ ion -Total number of electrons (16-1)=15.

Electronic configuration σ1s² < σ*1s² < σ2s² < σ*2s² < σ2p²(x) < π2p²(y)=π2p²(z)< π*2p¹(y)

Bond order =N(b)-N(a)/2 = 10-5/2 = 5/2 =2 1/2 O⁻₂ (super oxide ion): Total number of electrons (16+1)=17

Electronic configuration σ1s² < σ*1s² < σ2s² < σ*2s² < σ2p²(x) < π2p²(y)=π2p²(z)< π*2p² (y)=π*2p¹(z)

Bond order =N(b)-N(a)/2 = 10-7/2 = 3/2 =1 1/2

O₂⁺² ion :Total number of electrons (16-2)=14.

Electronic configuration σ1s² < σ*1s² < σ2s² < σ*2s² < σ2p²(x) < π2p²(y)=π2p²(z)

Bond order =N(b)-N(a)/2 = 10-4/2 = 6/2 =3

So bond order :O⁻₂ <O₂⁺<O₂²⁺

admin:

Related Questions

  1. The bad smelling substance, formed by the action of alcoholic caustic potash
  2. H₂ will not reduce which of following oxide?
  3. The atmospheric pressure is sum of the
  4. The products formed when diborane is hydrolysed are
  5. Which of the following possible isomers of butanol has a chiral centre