Navigate

The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV

The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is:

Options

(a) 30.2 MeV
(b) 23.6 MeV
(c) 2.2 MeV
(d) 28.0 MeV

Correct Answer:

23.6 MeV

Explanation:

Binding energy of two ₁H² nuclei = 2 (1.1 x 2) = 4.4 meV
Binding energy of one ₂He⁴ nucleus = 4 x 7.0 = 28 MeV
Energy released = 28 – 4.4 = 23.6 MeV

AIEEE2004
admin:

Related Questions

  1. The dimensions of magnetic field intensity B are
  2. If r be the distance of a point on the axis of a magnetic dipole from its centre
  3. A body has 80 microcoulomb of charge. Number of additional electrons in it will be
  4. A neutron moving with velocity v collides with a stationary particle
  5. Dimensional formula of magnetic field in terms of mass M, length L