The average power dissipated in a pure inductor is

Options

(a) VI²/4
(b) 1/2 VI
(c) zero
(d) VI²

Correct Answer:

zero

Explanation:

In the inductor circuit, phase difference (ɸ) = 90° or π / 2

we know that, Pₐᵥ = V(rms) I(rms) cos ɸ = V(rms) I(rms) cos(π/2)

Therefore, Pₐᵥ = 0