The amount of electricity requried to deposit 0.9 g of aluminium, when the electrode reaction is Al³⁺ + 3e⁻ → Al
Options
(a) 9.65 ˣ 10⁴ C
(b) 1.93 ˣ 10⁴ C
(c) 9.65 ˣ 10³ C
(d) 4.34 ˣ 10⁵ C
Correct Answer:
9.65 ˣ 10³ C
Explanation:
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For 27g of Al,
3 mole of electron=3F=289500c
For 0.9g of Al,
(289500/27)*0.9=9650