Navigate

The acceleration due to gravity near the surface of a planet of radius R and density d

The acceleration due to gravity near the surface of a planet of radius R and density d is proportional to

Options

(a) d/R²
(b) dR²
(c) dR
(d) d/R

Correct Answer:

dR

Explanation:

g=GM/R²
(M=Mass of the earth); (R=Distance of body from centre of earth)
g=G Volume x density / R²
Volume of the sphere=4/3 πR³
Therefore, g=G.4/3 πR³.d / R²
g=G 4/3 πRd
g=4πG/3.dR
g is proportional to dR

MP2002
admin:

Related Questions

  1. What is the time taken by moon light to reach earth?
  2. The masses of three wires of copper are in the ratio 1:3:5 and lengths
  3. The process of adding impurities to the pure semiconductor is called
  4. A generator at a utility company produces 100 A of current at 4000 V. The voltage
  5. In Young’s double silt experiment if the distance between the two slits