Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å

Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å. Another source S₂ is producing 1.02 x 10¹⁵ photons per second of wavelength 5100Å Then, (power of S₂) (power of S₁) is equal to:

Options

(a) 1
(b) 1.02
(c) 1.04
(d) 0.98

Correct Answer:

1

Explanation:

energy emitted/sec by S₁, P₁ = n₁ hc / λ₁
energy emitted/sec by S₂, P₂ = n₂ hc / λ₂
P₂ / P₁ = n₂ / n₁ . λ₁ / λ₂
= 1.02 x 10¹⁵ / 10¹⁵ . 5000 / 5100 = 1.0

admin:

Related Questions

  1. The dimensional formula for Young’s modulus is
  2. A conductor of length 5 cm is moved parallel to itself with a speed of 2 m/s,
  3. A DC ammeter has resistance 0.1Ω and its current ranges 0-100A. If the range
  4. A heavy nucleus at rest breaks into two fragments which fly off with velocities
  5. Order of e/m ratio of proton, α-particle and electron is