Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å

Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å. Another source S₂ is producing 1.02 x 10¹⁵ photons per second of wavelength 5100Å Then, (power of S₂) (power of S₁) is equal to:

Options

(a) 1
(b) 1.02
(c) 1.04
(d) 0.98

Correct Answer:

1

Explanation:

energy emitted/sec by S₁, P₁ = n₁ hc / λ₁
energy emitted/sec by S₂, P₂ = n₂ hc / λ₂
P₂ / P₁ = n₂ / n₁ . λ₁ / λ₂
= 1.02 x 10¹⁵ / 10¹⁵ . 5000 / 5100 = 1.0

admin:

Related Questions

  1. A body rolls down a stair case of 5 steps. Each step has height 0.1 m and width 0.1m
  2. A radiation of energy ‘E’ falls normally on a perfectly reflecting surface
  3. A focal length of a lens is 10 cm. What is power of a lens in dioptre?
  4. The angle between the two vectors A = 3i+4j+5k and B = 3i+4j-5k will be
  5. Assuming the sun to have a spherical outer surface of radius r