Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å

Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å. Another source S₂ is producing 1.02 x 10¹⁵ photons per second of wavelength 5100Å Then, (power of S₂) (power of S₁) is equal to:

Options

(a) 1
(b) 1.02
(c) 1.04
(d) 0.98

Correct Answer:

1

Explanation:

energy emitted/sec by S₁, P₁ = n₁ hc / λ₁
energy emitted/sec by S₂, P₂ = n₂ hc / λ₂
P₂ / P₁ = n₂ / n₁ . λ₁ / λ₂
= 1.02 x 10¹⁵ / 10¹⁵ . 5000 / 5100 = 1.0

admin:

Related Questions

  1. Suppose for some reasons, radius of earth were to shrink by 1% of present value,
  2. A radioactive substance decays to 1/16th of its initial activity in 40 days.
  3. An LCR circuit contains resistance of 100 ohm and a supply of 200 volt at 300 radian
  4. The vector sum of two forces is perpendicular to their vector difference. In that case,
  5. Out of the following options which one can be used to produce a propagating