Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å

Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å. Another source S₂ is producing 1.02 x 10¹⁵ photons per second of wavelength 5100Å Then, (power of S₂) (power of S₁) is equal to:

Options

(a) 1
(b) 1.02
(c) 1.04
(d) 0.98

Correct Answer:

1

Explanation:

energy emitted/sec by S₁, P₁ = n₁ hc / λ₁
energy emitted/sec by S₂, P₂ = n₂ hc / λ₂
P₂ / P₁ = n₂ / n₁ . λ₁ / λ₂
= 1.02 x 10¹⁵ / 10¹⁵ . 5000 / 5100 = 1.0

admin:

Related Questions

  1. The wetability of a surface by a liquid depends primarily on
  2. Two Carnot engine A and B are operated in series. The engine A receives
  3. Two coherent monochromatic beams of intensities I and 4I respectively, are superposed.
  4. A machine gun fires 10 bullets/s,each of mass 10 g,the speed of each bullet
  5. An electron is moving in a circular path under the influence of a transverse magnetic