Small drops of the same size are charges to V volt each. If n such drops coalesce to form a single large drop, its potential will be

Options

(a) Vn
(b) V/n
(c) Vn¹/³
(d) Vn²/³

Correct Answer:

Vn²/³

Explanation:

Potential at the surface of a solid charged sphere = (1 /4πε₀).(q / a)

(4/3) πr³ × n = (4/3) πr’³

Due to n changes, Vn = (1 /4πε₀).(nq / r’),

r’ = rn¹/³

Vn = (1 /4πε₀).(nq / n¹/³ r) = V n²/³