Point masses m₁ and m₂ are placed at the opposite ends of a rigid rod of length L,

Point Masses M And M Are Placed At The Opposite Physics QuestionPoint Masses M And M Are Placed At The Opposite Physics Question

Point masses m₁ and m₂ are placed at the opposite ends of a rigid rod of length L, and negligible mass. The rod is to be set rotating about an axis perpendicular to it. The position of point P on this rod through which the axis should pass so that the work required to set the rod rotating with angular velocity ω₀ is minimum, is given by

Point Masses M₁ And M₂ Are Placed At The Opposite Ends Of A Rigid Rod Of Length L Q 361Point Masses M₁ And M₂ Are Placed At The Opposite Ends Of A Rigid Rod Of Length L Q 361

Options

(a) x= m₂/m₁ L
(b) x= m₂L/m₁+m₂
(c) x= m₁L/m₁+m₂
(d) x= m₁/m₂ L

Correct Answer:

x= m₂L/m₁+m₂

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

AddThis Website Tools
admin:

Related Questions

  1. If a small sphere is let fall vertically in a large quantity of still liquid of density
  2. An electron in the hydrogen atom jumps from excited state n to the ground state
  3. A U²³⁵ reactor generates power at a rate of P producing 2×10⁸ fission per second.
  4. A radiotransmitter radiates 1 kW power at a wavelength 198.6 m. How many photons
  5. A Gaussian surface in the cylinder of cross-section πa² and length L is immersed