Oxidation state of sulphur in S₈, H₂S and S₂F₂ is

Oxidation state of sulphur in S₈, H₂S and S₂F₂ is

Options

(a) 0, -2, -1
(b) 0, 2, -1
(c) 1, -2, 1
(d) 0, -2, 1

Correct Answer:

0, -2, 1

Explanation:

Oxidation state of Sulphur in S₈ = 0,
Sulphur in H₂S = 2+x = 0, x = -2,
Sulphur in S₂F₂ = 2x + 2(-1) = 0,
2x – 2 = 0, x = 1.

admin:

Related Questions

  1. Which of the following is not soluble in NaOH
  2. In Zinc blende structure, the coordination number of the cation is
  3. 0.4g of silver salt of a monobasic organic acid gave 0.26g pure silver on ignition
  4. Platinum, palladium and iridium are called noble metals because
  5. The correct order of acidic strength of oxides of nitrogen, is