One mole of an ideal diatomic gas undergoes a transition from A to B along a path

One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figure.

The change in internal energy of the gas during the transition is

Options

(a) -20 kJ
(b) 20 J
(c) -12 kJ
(d) 20 kJ

Correct Answer:

-20 kJ

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

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  • ΔU = nCΔT
    Also, T = PV/nR
    Now,
    ΔT = T-T => [PV - PV] / nR
    ΔU = nR/¥-1 {PV- PV / nR} [here, ¥ = gamma]
    (nR will be cancelled out)
    We get,
    {-8 x 10^3} / {2/5} = -20kJ.

    Hope it helps :)

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