In Young’s double slit experiment, when wavelength used is 6000Å and the screen

In Young’s double slit experiment, when wavelength used is 6000Å and the screen is 40 cm from the slits, the fringes are 0.012 cm wide. What is the distance between the slits?

Options

(a) 0.24 cm
(b) 0.2 cm
(c) 2.4 cm
(d) 0.024 cm

Correct Answer:

0.2 cm

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. 1 a.m.u. is equivalent to
  2. Rutherford’s α-scattering experiment concludes that
  3. Dimensional formula for electrical resistance R is given by
  4. If oxygen has root mean square velocity of C m/s, then root mean square velocity of H
  5. A particle is moving such that its position coordinates (x,y) are (2 m,3 m) at time