In Young’s double slit experiment the distance between the slits and the screen

In Youngs Double Slit Experiment The Distance Between The Slits Physics QuestionIn Youngs Double Slit Experiment The Distance Between The Slits Physics Question

In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduces to half. As a result the fringe width

Options

(a) is doubled
(b) is halved
(c) becomes four times
(d) remains unchanged

Correct Answer:

becomes four times

Explanation:

Fringe width β = Dλ/d;
From qn D’ = 2D and d’ = d/2
β’ = λD¹ / d¹ = 4β

AddThis Website Tools
admin:

Related Questions

  1. Two wheels having radii in the ratio 1:3 are connected by a common belt
  2. The drift velocity of the electrons in a copper wire of length 2 m under
  3. The work function of sodium is 2.3 eV. The threshold wavelength of sodium will be
  4. The equation of state for 5 g of oxygen at a pressure P and temperature T,
  5. The most stable particle in Baryon group is