In which of the following compounds, nitrogen exhibits highest oxidation state

Options

(a) N₂H₄
(b) NH₃
(c) N₃H
(d) NH₂OH

Correct Answer:

N₃H

Explanation:

N₂H₄ ⇒ 2x + 4 (+1) = 0 ⇒ 2x + 4 = 0 ⇒ x = x -2. NH₃ ⇒ x + 3 (+1) = 0, ⇒ x = -3. N₃H ⇒ 3x + 1(+1) = 0 ⇒ 3x + 1 = 0. ⇒ x = -1/3. NH₂OH ⇒ x + 2 + 1(-2) + 1 = 0 ⇒ x + 1 = 0. ⇒ x = -1. Thus , highest oxidation state is -1/3.